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Mathematics 7 Online
OpenStudy (anonymous):

Which is equivalent to (3x) / (x-7) - (x+7)/x

OpenStudy (anonymous):

(2x^2+49)/x(x-7) (x^2+49)/x(x-7) (2(x+7)/x(x-7) 2(x-7)/x(x-7)

OpenStudy (anonymous):

\[(3x) \div (x-7) - (x+7) \div x\] Is that the formula?

OpenStudy (anonymous):

No. its fractions not divided by

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