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Please solve the linear quadratic system algebraically y=x^2-8x-12 y=4x+8
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\(\bf {\color{red}{y}}=x^2-8x-12\qquad \qquad {\color{red}{y}}=4x+8\\ \quad \\ \implies x^2-8x-12=4x+8\)
@cheergurl_99 Get it?
yeah but ima little stuck on how to solve it :(
Where? Can we see what you have done so far?
yeah sure one sec
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Shovel all the terms over on to one side, leaving 0 on the other. Then factor (if possible), complete the square, or use the quadratic formula.
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