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Solve |x| = 5
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Have you seen this..\[|x|=c \rightarrow x=\pm(c)\]
is x a real number?
wat
.-. look @Isaiah.Feynman explanation, its very detailed.
If \(x\) can be a complex number, then you're going to have: \[ (a-bi)(a+bi) = 5^2 \]Basically, any values \(a^2+b^2=25\) would work. (A circle of solutions) If it is a real number, then the only solutions are \(-5,5\). If it is only natural numbers, then the only solution is \(5\).
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