Question

help!!!!! Given ΔABC ~ ΔRBS, solve for y



triangle ABC side AC length 20 side BC length x and 10 side AB length y and 30 and interior triangle RBS with side RS length 8 side RB length 30 side BS length x

Answer 1

got picture?

Answer 2

here it is

Answer 3

\(\bf \triangle {\color{blue}{ ABC}} \sim \triangle {\color{red}{ RBS}}\implies \cfrac{{\color{blue}{ AR+RB}}}{{\color{red}{ RB}}}=\cfrac{{\color{blue}{ AC}}}{{\color{red}{ RS}}}\implies

\cfrac{{\color{blue}{ y+30}}}{{\color{red}{ 30}}}=\cfrac{{\color{blue}{ 20}}}{{\color{red}{ 8}}}\)

Answer 4

A. 0.83
B. 6.67
C. 45
D. 75
heres the options tho

Answer 5

well. if you solve for "y"... what would you get?

Answer 6

ok I did 8xy+30 got 8y +240 then did 30x20 got 600
nowihave 8y+240=600
is the answer 45??

Answer 7

is the answer 45?? \(\large \checkmark\)

Answer 8

thanks!!!!! :)