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Mathematics 11 Online
OpenStudy (anonymous):

how to find square root?

hartnn (hartnn):

you want to find square root of what ?

OpenStudy (anonymous):

wait..

OpenStudy (anonymous):

\[\sqrt{2\times32\times6.4\times10^6}+\sqrt{2\times50\times6.4\times10^6}\]

OpenStudy (anonymous):

i hav forget hw to find plz hlp me out my xam is near......

hartnn (hartnn):

lets first do the easiest thing, 3*32 = 64 2*50 =100 right ? now use, \(\Large \sqrt {☺ ☻} = \sqrt {☺} \sqrt {☻}\) so, \(\sqrt{64*6.4*10^6} = \sqrt{64}*\sqrt{6.4*10^6}\) do you know square root of 64 ?

hartnn (hartnn):

oh, a typo, its 2*32 = 64

OpenStudy (anonymous):

8

OpenStudy (anonymous):

okay a square root is the opposite of a square |dw:1393044972663:dw| So a square root is basically what you use to UNDO a square

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