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Write the equation of the tangent line of y=2cosx at x=-pi/2??
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to get equation of line, you'll need slope of tangent slope of tangent at x = -pi/2 = y' at x = (-pi/2) so first can you find the derivative of y ?
is the dervative of y=-sinx?
you mean \( y' = -2\sin x ?\)
then you just plug in x = -p/2 to get the slope \(m= -2 \sin (\pi/2 )\)
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