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Mathematics 19 Online
OpenStudy (anonymous):

If P(Eᶜ) = 0.53, then P(E) = ?

OpenStudy (anonymous):

1-.53

OpenStudy (anonymous):

Do you know why?

OpenStudy (anonymous):

I've seen similar problems with the graph but it's confusing for me to understand

OpenStudy (anonymous):

\[ P[E]+ P[E^c]=1 \]

OpenStudy (anonymous):

This is true for any probability P and any set E

OpenStudy (anonymous):

Your answer is P[E]= 1 - .53=.47

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