Question

At a certain instant a ball passes location ⟨0,20,0⟩ m. In the next 2 seconds, the ball's average velocity is ⟨0,26,0⟩ m/s. At the end of this 2 second time interval, what is the height y (in meters) of the ball?

Answer 1

in 2 seconds ball cover a distance \[26\times2 = 52 m\] so final coordinate of the ball is 20+52