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Mathematics 11 Online
OpenStudy (anonymous):

Using quadratic formula, solve the following quadratic equation for x

OpenStudy (lieutenantgeneral):

what u typed it wron

OpenStudy (uri):

@donmath Equation please. c:

OpenStudy (anonymous):

\[x ^{2}-4ax+4a ^{2}-b ^{2}\]

OpenStudy (anonymous):

is equal to zero

OpenStudy (anonymous):

guys anyone know

hartnn (hartnn):

you'll get the answer in therm of a,b compare your equation with \(Ax^2+Bx+C= 0 \) A= .. ? B = ... ? C = ....?

OpenStudy (anonymous):

The given equation is x 2 – 4ax + 4a 2 – b 2. On comparing the given equation with standard quadratic equation Ax 2 + Bx + C, we get A = 1, B = –4a, C = 4a 2 – b 2 The quadratic formula is: For the give equation,

OpenStudy (anonymous):

that i also know but tell me what is A and B and C

OpenStudy (anonymous):

a is cofficient of x b of y and c is for constant

OpenStudy (anonymous):

okay got it

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