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Calculus1
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find the general solution to the exact differential equation dy/dx=CSC^2(X)-42X^5
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\[\frac{ dy }{dx }=\csc ^2x-42 x^5\] \[y=\int\limits (\csc ^2x-42x^5)dx=\int\limits \csc ^2x ~dx-42\int\limits x^5~dx+c\] \[\left[ \int\limits \csc ^{2} x~ dx=-\cot x\right] \] complete it.
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