Question

If you are presented with the problem sin A= 0.45 and A is the angle you are searching for (it's an acute angle in a right triangle). How do you find angle A?

Answer 1

\(\bf sin(A)=0.45\implies sin^{-1}[sin(A)]=sin^{-1}(0.45)
\\ \quad \\
\implies \measuredangle A=sin^{-1}(0.45)
\)