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If the average (arithmetic mean) of 3a and 4b is less than 50, and a is twice b, what is the largest integer of a? Select one: a. 9 b. 11 c. 19 d. 20
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a=2b 3a=6b average of 3a and 4b is equal to average of 6b and 4b 6b+4b/2=5b 5b<50 then b<10 a=2b 2b<20 a<20 so the largest integer is 19.
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