Question

Using a directrix of y = 2 and a focus of (3, -4), what quadratic function is created?

Answer 1

f(x) = one twelfth (x - 3)2 - 1

f(x) = -one sixth (x + 3)2 + 1

f(x) = one sixth (x - 3)2 + 1

f(x) = -one twelfth (x - 3)2 - 1

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Answer 2

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