A 0.145 kg baseball is thrown from a platform above the ground at a 10 m/s. The ball is moving 15 m/s when it strikes the ground. From what height above the ground was the ball thrown?

Question

anonymous · Answer

$$v^{2}=v_{0}^{2}+2a(x-x_{0})$$

where v - is the end speed
v0 is the initial speed
a=g
x0 is what you are looking for
and x =0 .

i think that should do it

anonymous · Answer

if you are given the angle of impact i can be sure and the angle of the throw. than it's just ballistics\free fall

anonymous · Answer

grazcie it helped a lot c: