Question

Evaluating the integral of 8t^2 cos(t) dt, wondering where I missed something.

Answer 1

i take it your got stuck in a cycle?

Answer 2

by parts, derivative of 8t^2, integarte cos(t)

you get a few iterations till it zeros out

Answer 3

i made u=8^2 and dv=cost

Answer 4

integrate by parts again and again till it is free of x

Answer 5

good, if we table it up we get:

cos(t)
+ 8t^2 sin(t)
- 16t -cos(t)
+ 16 -sin(t)
- 0