Question

If P(A) = 0.6, P(B) = 0.55 and P(A and B) = 0.2 find the probabilities of

P (A or B)=?
P (not A)=?
P (not B)=?
p (A and (not B))=?
P (not (A and B))=?

Answer 1

P(AuB) = P(A)+P(B) - P(A and B)=.6 + .55-.2=.95

Answer 2

P( not A)= 1-P(A)=1-.6=.4
P( not B)= 1-P(B)=1-.55=.45

Answer 3

You can do the rest

Answer 4

Thanks so much!

Answer 5

YW

Answer 6

is P(A and (not B)) = .4275?

Answer 7

no

Answer 8

P(A and (not B)) = P(A) - P(A and B)=.6-.2=.4

Answer 9

P (not (A and B))= 1 - P(A and B)=1-.2=.8