Question

given the function h described by h(x)= 7/2x+2, find each of the following function values.
a. h(0)
b. h(-2)
c. h(-7)
d. h(y)

Answer 1

Do you know how to substitute?

Answer 2

i understood a but not the rest

Answer 3

How did you get a?

Answer 4

I plugged them in, but the other number gives weird fractions

Answer 5

Weird fractions are just fine.

Answer 6

They won't work into my assignment though

Answer 7

How can they not?

Answer 8

I don't know it just wasn't working

Answer 9

\[h(x)=\frac{7}{2x+2}\]
\[h(0)=\frac{7}{2(0)+2}=\frac{7}{2}\]\
\[h(-2)=\frac{7}{2(-2)+2}=\frac{7}{-2}\]
\[h(-7)=\frac{7}{2(-7)+2}=\frac{7}{-12}\]
\[h(y)=\frac{7}{2(y)+2}\]

Answer 10

For b I got -5 and it was right

Answer 11

\[h(x)=\frac{7}{2}x+2\]

Answer 12

Is that it?

Answer 13

the answer was -5

Answer 14

The one I am on now is k(-1)=1/2(-1)+6

Answer 15

That would be -1/2+6=5 1/2