Question

solve the inequality. 3 + |t + 4| < 10

A.
–11 < t < 3

B.
t > 3 or t < –11

C.
t < 3 and t > 11

D.
–3 < t < 11

Answer 1

anyone

Answer 2

3 + |t+4| < 10

3 - 3 + |t+4| < 10 - 3

|t+4| < 7

Answer 3

Then,

+(t+4) < 7 and -(t+4) < 7

Answer 4

Remember that when working with inequalities, the sign changes when multiplying or dividing by negative values.

Answer 5

Sorry, not the sign, the inequality changes--i,e, > becomes < or vice versa.