Question

derivative of -x^2+x

Answer 1

\[ax^n=anx^{n-1}\]where "a" is a constant, and n is any real number

Answer 2

remember x = x^1 and x^0 = 1

Answer 3

Now knowing this, what do you think the answer is?

Answer 4

@ChmE meant to write (d/dx)(ax^n) = a n x^(n-1)