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OpenStudy (anonymous):
determine the number of Cr atoms in 50.00 grams of CrCl3
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OpenStudy (anonymous):
covert 50 grams of CrCl3 into moles. Then do the mole to mole ratio when there is one mole of Cr to 1 mole of Cl3. Then use avogadro's number (6.022 e23 atoms) to get atoms of Cr....is that correct?
OpenStudy (joannablackwelder):
Looks right to me. :)
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