Question

Verify that quadrilateral BCDE is a rhombus with vertices B(-5, 1), C(0, 6), D(5, 1) and E (0, -4) by showing that all four sides are equal.
A. BD = CE = square root of 50
B. BD = CE = 50
C. BC = CD = DE = EB = 50
D. BC = CD = DE = EB = square root of 50

Answer 1

D.
B(-5, 1), C(0, 6)
\[
\sqrt{ (6-1)^2+(0-(-5))^2 }=\sqrt{50}
\]

Answer 2

It is D

Answer 3

Thank you :)

Answer 4

YW