Question

the point (8,-15) is on the terminal side of an angle pie.what is sin pi?

Answer 1

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Answer 2

(8,-15) = (x, y)
\[r^2 = x^2+y^2 \rightarrow r^2 = (8)^2+(-15)^2\]
\[\rightarrow r^2 = 64 + 225 = 289 \rightarrow r = 17\] ( where r is the hypotenuse)
Now,

\[\sin \pi = \frac {y}{r} \rightarrow \sin \pi = \frac {-15}{17}\]

@zebulin

Answer 3

thank you so much !

Answer 4

help wiith another?

Answer 5

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