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OpenStudy (anonymous):
will give medals factor 2g^3 - g^2 - 8g + 4
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OpenStudy (anonymous):
(g+2)(g-2)(2g-1)
OpenStudy (anonymous):
\[g^2\left( 2g-1 \right)-4\left( 2g-1 \right)=\left( 2g-1 \right)\left( g^2-4 \right)\] =(2g-1)(g+2)(g-2)
OpenStudy (anonymous):
thats not one of my option
OpenStudy (anonymous):
2nd option
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