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what is the solution to the rational equation
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\[\frac{ x }{ 2x + 1 } - \frac{ 1 }{ 4 } = \frac{ 2 }{ 2x + 1 }\]
A) x = 9 over 2 B) x = 7 over 2 C) x = 2 D) x = 3
\(\bf \cfrac{ x }{ 2x + 1 } - \cfrac{ 1 }{ 4 } = \cfrac{ 2 }{ 2x + 1 }\qquad {\color{red}{ \times 4(2x+1)}} \\ \quad \\ {\color{red}{ 4\cancel{(2x+1)}\times }}\cfrac{ x }{ \cancel{2x + 1} } - {\color{red}{ \cancel{4}(2x+1)\times }}\cfrac{ 1 }{ \cancel{4} } = {\color{red}{ 4\cancel{(2x+1)}\times }}\cfrac{ 2 }{ \cancel{2x + 1} }\) then solve for "x"
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