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Probability
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Martha, Lee, Nancy, Paul and Arando have all been invited to a dinner party. They arrive randomly an each person arrives at a different time.
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In how many ways can they arrive? 5! = 120 right
In how many ways can Martha arrive first and Armando last? Help with this one, please
I was thinking 3*2*1=6
3! is correct
Cuz Martha and Armando must be first and last
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Soooo Only 3 of the guys can be "moved" around
I was thinking that, but then I thought: M * 4 * 3 * 2 * A That would give 24
Nope that is incorrect logic
Ok, just making sure, thx. Can you help w/ another one?
Umm ya If i can be of assistance
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