Question

a circle is inscribed in an equilateral triangle with a side of 6cm. find the area that is part of the triangle but not he circle

Answer 1

\[area~of~\triangle=\frac{ 1 }{2 }*6*3\sqrt{3}=9\sqrt{3}\]
\[area ~of~circle=\pi r^2=\pi \left( \sqrt{3} \right)^2=3\pi \]
required area=? (find the difference)

Answer 2

thanks!

Answer 3

yw