WILL AWARD MEDAL/FAN!!! COMES WITH FREE OREOS AND A CERTIFICATE FOR HELPING ME!!! The product of the least and greatest of three consecutive negative odd integers is 221. Find the three integers.
-x * (-x - 4) = 221 x^2 + 4x = 221 x^2 + 4x - 221 = 0 (x + 17)(x - 13) = 0 x = -17, 13 the numbers are -13, -15, and -17.
What are your three consecutive NEGATIVE ODD integers, if I may ask?
i wrote them -13,-15 and -17
No, what I mean is, are your consecutive integers: -x,-x-2, and -x-4?
yeah actually..:)
Well, one tutor (can't tell you where exactly, mind you) told me that it was -x, -x-1, and -x-3. Another told me that it was -x, -x-2, and -x-4. Which are correct? Are they both the same or not?
see u can use any..!! while u'll be getting the same answer.. !
How did you get 13 in your answer?
no they are not the same. the first is incorrect. lets say x=5. so first integer is -5 next is -5-1 which equal -6 and -6 is not an odd integer
So, what should it be, @nikato ?
well i was answering ur previous question, are they both the same or not? no because like i said above, -x,-x-1,-x-3 does not give us consecuive odd integers. however the other is right. -x,-x-2,-x-4 will give u consecutive odd integers
Oh. I see. So what @aayushi.somani was right?
correct. and to answer ur other question (x + 17)(x - 13) = 0 which was in his/her work and u can seperate to x+17=0 or x-13=0 so x=-17 or x=13 but since the question asks for ODD integer, u can disgard the positive 13
sorry, i accidentally closed this window and had to reopen it
Oh, it's alright. LOL. As long as you are helping me, obviously, it's alright. xD
ok.. no problem
So even if your answer is positive 13, then you could just take it for a negative 13?
no.. the positive 13 has be rejected.. and we have the keast negative value -17 soo v will now count for 2 more consecutive odd negative no.
Okay. Thank you
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