Question

simplify the expression 27x^-3y^-7/36x^-3y

Answer 1

well its simply

\[\frac{27}{36} \times \frac{x^{-3}}{x^{-3}} \times \frac{y^{-7}}{y^1}\]


so simplify the numbers at the start

then use the index law for division is subtract the powers

\[\frac{x^a}{x^b} = x^{a -b}\]

and you'll get the answer...

remember the index law for a power of zero...

\[a^0 = 1\]

you'll need it for this question.