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factor each completely 15x2 - 18y2
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Uhm, the only thing you can factor is a 3.. \[\LARGE 3(5x^2-6y^2)\]
\[15x^2-18y^2\]take 3 common\[3(5x^2-6y^2)\]\[a^2-b^2=(a+b)(a-b)\]so,\[(5x^2-6y^2)=(5x+6y)(5x-6y)\]\[3(5x+6y)(5x-6y)\]
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