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How do I find B in this triangle?
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@agent0smith @ganeshie8
Use either sine, cosine, or tangent, whichever you like.
I cannot remember how to use those.
you can use the sine law that says the (sineA)/a = (SineB)/b = (sineC)/c
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|dw:1393439512307:dw|
Sorry I am very rusty with geometry. Just started geometry 2 so I'm trying to catch up. So how do I use sine to find B?
You can find them all on google but sine = opposite/hypotenuse cosine = adjacent/hypotenuse Tangent = opposite/adjacent
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