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\[\sin 35 = \frac{ opposite \ side }{ hypotenuse } = \frac{ x }{ 15}\]\[x = 15 \times \sin 35 = 15 \times = 8.60 = 8.6 m \] got it :) ?
No, this is so confusing for me, I'm sorry.
|dw:1393442193511:dw|
now \[\sin \theta = \frac{ opposite \ side }{ adjacent side }\]\[\cos \theta = \frac{ adjacent \ side }{ hypotenuse }\]\[\tan \theta = \frac{ opposite \ side }{ adjacent \ side }\] these r called trignometric ratios and i hope u know about them,..... now in ur problem |dw:1393442438935:dw|
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