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What is the turning point of the graph of f(x) = |4x| + 2 ?
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let's take a peek at |4x| expression only for now what value for "x" makes that expression 0?
ummm... 0?
yeap that means that the VERTEX or "turning point" is at \(\large \begin{array}{llll} |4x| + {\color{red}{ 2}} \\ \quad \\ |4({\color{red}{ 0}})| \\ \quad \\ ({\color{red}{ 0}}, {\color{red}{ 2}})\Leftarrow \textit{vertex or "turning point"} \end{array}\)
Thank you!!
yw
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