Question

What must be added to 3x -7 to make x^2 + 4x -1?

Answer 1

to make \(3x\) got to \(4x\) we add \(x\)
to make \(-7\) got to \(-1\) we add \(6\)
to make \(0\) go to \(x^2\) we add \(x^2\)
so in all we add \(x^2+x+6\)
and we see
\((3x-7)+(x^2+x+6)=3x-7+x^2+x+6=x^2+3x+x+6-7 = x^2+4x-1\)

Answer 2

\((3x-7)+(x^2+x+6)=3x-7+x^2+x+6=x^2+3x+x+6-7\\ = x^2+4x-1\)

Answer 3

sorry that got cut off...