Question

The side length of a square is (x - 4)^2 units. What is the perimeter of the square? *
x^2 - 8x + 16
4x^2 - 32x + 64
x^2 + 16
4x^2 + 64

Answer 1

Wow harddd stuff

Answer 2

whats the answer

Answer 3

perimeter of a square with side \(x\) is \(4x\)
so
\(4(x-4)^2 = 4(x^2-8x+16) = \ \large ? \)

Answer 4

whats the answer???