Solve each of these systems using the substitution method.
2x + 3y = -4

x − 2y = 5

x = 1, y = -2
x = -1, y = 2
x = 1, y = 2
x = -2, y = -1

Question

Solve each of these systems using the substitution method.
2x + 3y = -4

x − 2y = 5

x = 1, y = -2
       x = -1, y = 2
       x = 1, y = 2
       x = -2, y = -1

darkigloo · Answer

Isolate one of the variable in one equation. It's easier to do this with x-2y=5. 
$$x - 2y =5 $$
$$x = 5 + 2y $$
Now that you have x, plug it into the other eqation and solve for y.

anonymous · Answer

its 7

darkigloo · Answer

$$2x + 3y = -4 $$
$$2(5 + 2y) + 3y = -4$$
$$10 + 4y + 3y = -4$$
$$10 + 7y = -4$$
$$7y = -4 - 10$$
$$7y = -14$$
$$y = -2$$
Do you get how I got -2?

darkigloo · Answer

To find x, just plug in x=-2 into x-2y=5.