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Help please: 2cos^2x-cosx=1 what's x?
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les y = cos(x) then solve 2y^2-y-1 =0 then plug in for y at the end
let*
\(\bf 2cos^2x-cosx=1\implies 2{\color{red}{ cos}}^2{\color{red}{ (x)}}-{\color{red}{ cos}}{\color{red}{ (x)}}-1=0\) <---- notice tis just a quadratic equation, thus solve it likewise
pretty
ok I will try thanks
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