Question

Help! I will medal!!
Given the function f(x) = 2x, find the value of
f−1(32).

f−1(32) = 0

f−1(32) = 1

f−1(32) = 5

f−1(32) = 16

Can someone go through the steps for me!!

Answer 1

f−1(32) = 16.
Because, 2^x=32
Then you make them both have the same base, so we then have
2^x=2^16. We can then eliminate the bases so,
x=16.
f^-1(x)=16
f^-1(32)=16