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a tennis player hits a ball 1 meter above the ground with a velocity of 20 meters per second. When will the ball hit the ground?
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at what angle? straight up?
I would guess horizontally...
I believe that it is horizontally, it doesn't say specifically though.
if horizontally final position = 0 = 1 meter - (1/2)(9.8m/s^2) t^2
Solve that for \(t\), then find the horizontal distance traveled by \(d = st\) where \(s = 20 \text{ m/s}\)
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