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Solve. Find exact solutions: √(6+2x)-2=2
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start by adding \(2\) to both sides
you get \(\sqrt{6+2x}=4\) square both sides and get \[6+2x=16\] then solve that one
x=5
what about this one\[\sqrt{4x-11}+2=\sqrt{6x-5}\] its really giving me trouble gecause its different. sorry for bothering
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