Question

Evaluate the integral:

Answer 1

Im not sure where to begin with this problem :/

Answer 2

trig sub

Answer 3

start
let x=4sin(theta)

Answer 4

\[x=4\sin \theta \rightarrow dx=4\cos \theta d\]

Answer 5

\[I=\int\limits_{?}^{?}\frac{ 16\sin ^{2}\theta }{ \sqrt{16-16\sin ^{2}\theta} }*4\cos \theta d \theta=\int\limits_{?}^{?}\frac{ 16\sin ^{2}\theta }{4\cos \theta }*4\cos \theta d \theta=\int\limits_{?}^{?}16\sin ^{2}\theta d \theta\]

Answer 6

CRC STANDARD MATH. TABLES
integral 121 p.397 too complex to put there
but has quadratic in x times sqrt(16-x)