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how to integrate by substitution for (x^2+1)/(x+1) ?
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thank you for ur time, but im not taught using sin cos..
\[ \frac{x^2+1}{x+1} = \frac{x^2-1+2}{x+1} = \frac{(x-1)(x+1)+2}{x+1}=x-1+\frac{2}{x+1} \]
You can let \(u = x+1\)
wio how do u get x2+1= x2-1+2?
\(1 = 2-1 = -1 + 2\)
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hmm ok thx!
why are both the answers so diff? im confused :(
x²-x+2ln(x+1)
|dw:1393480545142:dw|
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