Question

i^18

Answer 1

SIMPLIFY

Answer 2

(i^2)^9 = (-1)^9 = -1

Answer 3

we know i^2=-1
i^18=i^2*i^2*i^2.....9 times...=(i^2)^9=(-1)^9=-1

Answer 4

thank you so much.... do you know by any chance (3−2i)/(7+i)

Answer 5

\[\frac{ 3-2i }{ 7+i } *\frac{ 7-i }{ 7-i }\]

Answer 6

\[\frac{ (3-2i)(7-i) }{ (7^2)-i^2 }\]

Answer 7

\[\frac{ (3-2i)(7-i) }{ 49+1 }=\frac{ (3-2i)(7-i) }{ 50 }\]

Answer 8

once again thank you very much :) you really helped me out

Answer 9

wlcme :)