Question

find all real and complex zeros of p(x)=x^3-x^2-4x-6

Answer 1

p(x) = x³ - x² - 4x - 6
= (x - 3) (x² + 2x + 2) ........ will be 0 if either factor is 0
x - 3 = 0 .... ⇒ x = 3
x² + 2x + 2 = 0
(x + 1)² = -1 .... ⇒ x = -1 ± i

Answer: x = 3, -1 ± i