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What is the equation of the line that passes through (–2, 3) and is parallel to 2x + 3y = 6?
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let equation of line is y=mx+c you know slope m by given equation of line 2x + 3y = 6 m=-2/3 by putting value of m you will get y=(-2/3)x+c now put point (-2,3) in this line and get c and after put value of c in same equation
sooo whats the answer
please calculate it by own and you tell me final answer.
im trying to get this answer quick i have a time limit please tell me
continuing from above y=(-2/3)x+c now put point (-2,3) in this line and get c so value of c =5/3 now equan is 2x+3y=5
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