Question

What is the equation of the line that passes through (–2, 3) and is parallel to 2x + 3y = 6?

Answer 1

let equation of line is y=mx+c
you know slope m by given equation of line 2x + 3y = 6
m=-2/3
by putting value of m you will get y=(-2/3)x+c now put point (-2,3) in this line and get c
and after put value of c in same equation

Answer 2

sooo whats the answer

Answer 3

please calculate it by own and you tell me final answer.

Answer 4

im trying to get this answer quick i have a time limit please tell me

Answer 5

continuing from above
y=(-2/3)x+c now put point (-2,3) in this line and get c
so value of c =5/3 now equan is
2x+3y=5