An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.9t2 +19.6t + 58.8. What is the object's maximum height?

A. 58.8
B. 194.04
C. 78.4
D. 117.6

Question

An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.9t2 +19.6t + 58.8. What is the object's maximum height? 


A. 58.8 
 B. 194.04 
 C. 78.4 
 D. 117.6

kamibug · Answer

Welcome to Openstudy! =D

kamibug · Answer

I don't know the answer. I know I did this in my math class last year but I don't remember how. Maybe this website can help you. www.quickmath.com 
Hope it helps! =)

anonymous · Answer

time=distance/speed
58.8miles/19.6miles/second
t=3s
thus:
h=-4.9(9)+19.6(3)+58.8=73.5
thats what av gotten though not in your choices