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Solve. –6 ≥ 10 – 8x A. x ≥ –2 B. x ≤ –2 C. x ≥ 2 D. x ≤ 2
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\(\large –6 \ge 10 – 8x\)
add 8x both sides
\(\large –6 \ge 10 – 8x\) \(\large –6+8x \ge 10 \)
next add 6 both sides
2 and 18
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hey its "8x" not just "8"
we cannot add apples and coconuts
ok
so, -6 and 8x will stay like that, we dont add them away ok :)
so its 2x and 18x
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ok
so C?
\(\large –6 \ge 10 – 8x\) add 8x both sides : \(\large –6+8x \ge 10 \) add 6 both sides \(\large 8x \ge 16\) divide 8 both sides \(\large x \ge 2\)
Yes !!
tnx
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u wlc :)
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