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Solve. 5 + d > 5 – d A. d > 10 B. d > 0 C. d < –5 D. d > –10
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start by adding "d" both sides
ok
5 + d > 5 – d add "d" both sides : 5 + 2d > 5
next subtract 5 both sides
ok
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wat do u get ha
5 + 2d > 5 -5 -5
0 and 2d
yes ! 2d > 0
next divide "2" both sides
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2d > 0 /2 /2
1 and 0
\(\large \color{red}{\checkmark}\)
d > 0
so b?
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yup !
tnx
np :)
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