Question

X^2+3x-10

Answer 1

find two numbers the product is -10 and the sum is 3..
a*b=-10
a+b=3
try 5 and -2, the order doesn't matter
5*-2=-10
5+(-2)=3
x^2+ (5x-2x) -10=0
x^2-2x+5x-10=0
x(x-2) + 5(x-2)=0
(x+5)+(x-2)=0
roots are -5 and 2