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Can i have some algebra 2 help? http://prntscr.com/2wlup1
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@wolfe8
finding the vertex should narrow it down
write it as \(12y=x^2\) then it looks like \(4py=x^2\) oh hello!
since its a positive first term, the focus is above the vertex, the directrix beneath it and the focus and vertex share the same x part
Im sorry i dont understand any of this :|
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How bout this? http://hotmath.com/hotmath_help/topics/finding-the-equation-of-a-parabola-given-focus-and-directrix.html I gots to go to class.
thanks
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