Question

How do you find the real number solution of y^3-5y^2=0??

Answer 1

factoring helps ...

Answer 2

we know y=0 is a solution, so assume y not equal to 0

y^3 - 5y^2 = 0

y^3 = 5y^2 ; divide by y^2

y = 5 will be another solution.

Answer 3

there will be one more solution such that:

y(y-5)(y-r) = y^3 - 5y^2